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Reduced density operator/matrix and partial trace | ||||||||||||
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The reduced density operator is an application of the density operator. The reduced density operator is so useful it is indispensable in the analysis of composite quantum systems [NC10, Sec. 2.4.3]. Consider a composite system, with density matrix , consisting of Alice’s system and Bob’s system, there is often a need to express the state of Alice’s or Bob’s system in terms of . The operation that takes us from to (denoting Alice’s density matrix) or (denoting Bob’s density matrix) is called the reduced density operator. The reduced density operator for Alice’s system is defined by where is a map of operators known as the partial trace over Bob’s system. Suppose and are any two vectors in Alice’s state space, and furthermore, and are any two vectors in Bob’s state space, then the partial trace is defined by the operation [NC10, (2.178)]: Above, the notation is equivalent to To see why the definition above makes sense, suppose a quantum system is in the product state , where and are the density matrices for subsystems and respectively, then since the trace of any density matrix is 1. Similarly, In general, if where is an orthonormal basis of , and is an orthonormal basis of , then the partial trace over is [WN17, Definition 1.6.1]: For a quick summary of discussion up to this point, watch edX Lecture 1.7 “The partial trace” of Quantum Cryptography by CaltechDelftX QuCryptox. Consider the pure (entangled) Bell state: . The system comprises 1️⃣ single-qubit subsystem with basis vectors and , and 2️⃣ single-qubit subsystem with basis vectors and . This system is entangled (i.e., not separable) because , but using the reduced density operator, we can find a full description for subsystem and for subsystem . The density matrix for the system is: Applying Eq. (1), the reduced density operator for subsystem is: Since , both and are mixed states. 🤔 How do we reconcile the preceding observation ☝ with the fact that is a pure state?
The strange property, that the joint state of a system can be pure (completely known) yet a subsystem be in mixed states, is a hallmark of quantum entanglement.
⚠ Caution [KLM07, Exercise 3.5.5]
The partial trace contains all the relevant information about subsystem if subsystem is discarded. Similarly, contains all the relevant information about subsystem if subsystem is discarded. These local descriptions do not in general contain enough information to reconstruct the state of the whole system. Expressing a bipartite vector in the Schmidt basis makes it much easier to compute the partial trace of either subsystem. For this reason, let us discuss Schmidt decomposition. References
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